DemistoUploadFileV2 Deprecated

Source

from typing import Tuple

from CommonServerPython import *


def upload_file(incident_id: str, entry_id: str, body: str = '', as_incident_attachment: bool = True):
    service_name = 'incident' if as_incident_attachment else 'entry'
    return demisto.executeCommand("core-api-multipart",
                                  {"uri": f'{service_name}/upload/{incident_id}', "entryID": entry_id, "body": body})


def upload_file_command(args: dict) -> Tuple[str, str]:
    incident_id = args.get('incidentID', '')
    entry_id = args.get('entryID', '')
    body = args.get('body', '')
    target = args.get('target', 'war room entry')
    response = upload_file(incident_id, entry_id, body, target == 'incident attachment')
    if is_error(response[0]):
        raise Exception("There was an issue uploading the file. Check your API key and input arguments.")

    uploaded_entry_id = demisto.dt(response, 'Contents.response.entries.id')
    readable = 'File uploaded successfully.'
    # in case the file uploaded as war room entry
    if uploaded_entry_id:
        readable += f' Entry ID is {uploaded_entry_id}'
    if body:
        readable += f'. Comment is:{body}'

    return readable, response


def main():
    try:
        readable, response = upload_file_command(demisto.args())
        return_outputs(readable, {}, response)
    except Exception as err:
        return_error(str(err))


if __name__ in ['__main__', 'builtin', 'builtins']:
    main()

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